Saturday, March 13, 2010

Revision of Mean Value Theorem

1) we all have an idea of what the mean value theorem is and we are doing this entry because of some unclear area in this topic. the mean value theorem finds a point in the given interval that is parallel to two points a and b also in the interval there are certain condition the graph most pass before the mean value theorem can be used and give a definite answer. off the back i do not know the conditions but i believe those conditions are the function must be continuous and differentiable. if it passes that, then the mean value theorem can be used. the equation that i am going to use is √(x) in the interval [0, infinity). REMEMBER the point of the blogs is to show an understanding so I'm going to show u my understanding with this simple Graph. the graph look like this











I'm going to choose x=4, and x=9 for a and b. the out put for x=4 is 2 and for x=9 is 3. simple rite. using the mean value theorem we get a slope of 1/5 . doing the math the point x=25/4 would have an instantaneous slope of 1/5. the tangent line would be y = (x/5)+(5/4) which is going to be represented by the green line. f(a) = 4 and f(b)=9. the secant line witch is not in the graph would have the same slope as the green line y=(x/5)+(5/4).

7 comments:

  1. rafa im your first comment on this yay ... no

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  2. Hm...this is a good explanation of how to find a tangent line at a point, but I honestly don't see the mean value theorem anywhere.

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  3. Genius at work ? :O

    I think you need to step it down a level ? lol and explain the mean value theorem mroe

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  4. i think i do see the mean value theorem..

    when you say the slope of the secant line would have the same slope as the green line ..

    the slope would be ..f(b)-f(a) / b-a..

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  5. thank you Javier for explaining my work

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